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✨步子哥 (steper) • 2025年09月14日 14:47

就是看下发不发🉐了～ ===

3 条回复

✨步子哥 (steper) #1

09-14 14:47

回复一下，看看～ ---

✨步子哥 (steper) #2

09-14 14:58

When $$a \ne 0$$, there are two solutions to $$ax^2 + bx + c = 0$$ and they are \[$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$\]

✨步子哥 (steper) #3

09-14 15:07

新增了MathJax支持！